Wednesday, 28 April
(5 points) You MUST show work!
It takes two gardeners 8 days to mow a lawn.
One is lazy and one is energetic.
The energetic one would only take 12 days to mow it on his own.
How many days would the lazy gardener take to mow the lawn on his own?
Solution:
The energetic gardener would be able to mow the lawn in twelve days. In eight days he would be able to mow 8/12 of the lawn.
This leaves 4/12 of the lawn left for the lazy gardener to mow. He takes the full eight days to do this so he mows only half as quickly as the energetic one.
He would therefore need 24 days to mow the lawn on his own.
Twice as long as the energetic one.
Winner: Carlota De Armas
Tuesday, 27 April
Find three consecutive odd integers whose sum is 369.
(3 points)
Answer:
121, 123, 125
Winners: Marta S., Paula G. and Carlota D.A.
Friday-Monday, 23-26 April
Unit Fraction Problem
Find seven different unit fractions whose sum is 1. In other words, determine the values for a, b, c, d, e, f, and g in the following equation:



where a, b, c, d, e, f, and g are all different positive integers.
(5 points)
Solution to Problem:
2 6 8 12 20 24 30
or
3 5 6 8 10 20 40
or
2 4 8 16 36 48 72
or
2 4 8 16 32 34 544
or
3 4 6 9 13 18 156
or
3 5 6 9 12 18 20
or
3 4 7 8 14 24 28
Wednesday, 21st April
When the Workers Relax
Seven workers, Amie, Benny, Carol, David, Eric, Franklin, and Grace have a day off every week, no two of them on the same day.
You are told that Amie’s day off is the day after Carol’s;
that David’s day off is 3 days after the day before Eric’s;
that Benny’s day off is 3 days before Grace’s;
that Franklin’s day off is half way between Benny’s and Carol’s;
and that Franklin’s day off is Thursday.
Which day off does each worker have?
(4 points)
| DAY OFF | WORKER |
| Sunday | Amie |
| Monday | Eric |
| Tuesday | Benny |
| Wednesday | David |
| Thursday | Franklin |
| Friday | Grace |
| Saturday | Carol |
Tuesday, 20th April
In an isosceles triangle with vertices labeled A, B, and C, side AB is twice as long as side AC. If the perimeter is 200 meters, how long is side BC?
Hint: In an isoceles triangle two sides are equal.
(3 points)
Answer: 80 meters
Winner: Paula Gago
Challenge Problems: 19th April
Problem 1
The Math Teacher’s Fish (5 points)
When Mr. Lowe returned from his fishing trip, his students inquired as to the length of his prize catch.
Mr. Lowe answered,
“The head measured 9 inches.”
“The tail was as long as the head and half the body.”
“The body was as long as the head and tail.”
How long was Mr. Lowe’s prize fish?
Solution:
1. Let H, B, and T be three variables representing the Head, Body, and Tail of the fish.
2. H = 9″.
3. T = H + 1/2 B
4. B = H + T
5. So, B = 9 + 9 + 1/2 B, by substitution.
6. Therefore, B = 36″.
7. So, T = 9 + 18 = 27″.
8. The Fish = H + B + T or 72″ in length.
Problem 2
(3 points)
Terry’s restaurant offers a 7-½ % discount for senior citizens. If a group of seniors paid $52.18 for lunch after the discount, what would they have paid without the discount?
Answer $56.41
Problem 3
(2 points)
Al’s father is 45. He is 15 years older than twice Al’s age. How old is Al?
Answer:
| Twice Al’s age is 2 x 15: | 30 |
| 15 more than 30 is 15 + 30: | 45 |
Wednesday, 24 & Thurday, 25
The 100 Meter Race Problem
A Sherando boy and a Handley girl ran a 100 meter race. The Handley girl crossed the finish line when the Sherando boy had gone 95 meters, so she won the race by 5 meters.
When they raced a second time, the Handley girl wanted to make the contest more even so she handicapped herself by starting 5 meters behind the start line.
If the two ran at the same constant speed as before, who won the second race? Explain (or give their times relative to each other).
(6 Challenge points) To the first 5 students of each group to publish the correct answer in the blog. Post your answer here!!!!!
Solution to Problem:
The Handley girl runs 100 meters in the same time that the Sherando boy runs 95 meters; therefore, the rate of the girl is 100 meters per some unit of time and the rate of the boy is 95 meters per the same unit of time.
Below is the Rate-Time-Distance table for the second race:
| Runner | Rate | Time | Distance |
| Boy | 95 m/unit | 100/95 units | 100 m |
| Girl | 100 m/unit | 105/100 units | 105 m |
So the Boy’s time is 100/95 or 1.05266316 units of time, and the Girl’s time is 105/100 or 1.05 units of time. Therefore, the Handley Girl won the second race as well! She passed the Sherando Boy at 95 meters
Monday, 22 March & Tuesday, 23 March
LOOK FROM DIFFERENT PERSPECTIVES!!!!
In this 4×4 grid of circles, how many different sets of four circles form the corners of a square (of any size)? One such set is shaded for you.
(4 Challenge points) To the first 5 students of each group to publish the correct answer in the blog. Post your answer here!!!!!
Answer: 20


Friday, 19 March
There are 7 secondary schools in the town of Newtonville. Each school has a different total number of 1º ESO students. School A has three fewer students than school B; school B has three fewer than school C; school C has three fewer than school D; school D has three fewer than school E; school E has three fewer than school F; school F has three fewer than school G. If there are 2037 1º ESO students in the town of Newtonville, how many 1º ESO students are in the school with the least amount of 7th graders?
(5 Challenge points) To the first 5 students of each group to publish the correct answer in the blog. Post your answer here!!!!!
Answer: 282 Students
Winner: Paula Gago
Thursday, 18 March 2010
1. Jennifer wants to buy a new hockey puck that costs 5.25€. She has 2.30€. She can earn 50 cents an hour by raking leaves. How many hours will she have to work to get the money she needs?
(3 Challenge points) To the first 5 students of each group to publish the correct answer in the blog.
Answer: 6 hours
Winner: Erik Déniz and Lorena
Wednesday, 17 March 2010
{7 + 4 · 3 – [(-2)2 · 2 - 6)]}+ (22 + 6 – 5 · 3) + 3 – (5 – 23 : 2) =
Answer: 14
Winner: Marta Sangrá
(3 Challenge points) To the first 5 students of each group to publish the correct answer in the blog. Post your answer here!!!!!
————————-
Monday, 15 March 2010
No winners
(3 Challenge points) To the first 5 students of each group to publish the correct answer in the blog.





Hello Carmen Ana,
I´m not sure that my answer is correct, but I did this operation and my result was 32.
See you tomorrow,
Paula
Hello Carmen Ana,
The answer to the challenge problem on Wednesday 17th March is 48.
See you tomorrow,
Lorena
The answer is 14.
hello Carmen Ana i´m trying to do the challenge and the aswer of the wednesday 17th is 48
and one thing the challenge of monday 15th we can do it
Sorry, I confuse,the total is 38.
See you tomorow,
Lorena =)
hello Carmen Ana I put 48 bbut then i thit it again and get me 32 what is good
Hello Carmen Ana, the answer for the challenge on Wednesday 17th March is 24.
Kisses,
Alejandra
sorry carmen ana, my final answer is 14
Kisses
Is 14
Hello again Carmen Ana,
I do It again and it gave me:14
Lorena
Only ONE answer per person.
Sorry!
Hello Carmen Ana the answer for th challege is 24
see you tomorrow.<<
i confiuse is 14 see you tomollow
hello Carmen Ana my answer for today’s challenge is 6 hours and she has 5 cents more. Bye and good night
Hello Carmen Ana,
the answer of today is: she has to work 6 hours to have 2,95 and she gets 5 cents more.
Kisses,
Lorena
The answer is 6 hours.
are 412 stundents
The answer to the challenge problem of friday 19th is….291
The solucion for the challenge of Friday 19th is A with 282
Hello Carmen Ana the answer for Friday´s challenge is 491 students
Bye see you tomorrow.
The chalenge for today Monday 22th is 9
14
15
My answer for today’s challenge is 10
9
the answer is 4
i think is 17
Hi Carmen Ana
You put that we neet to try anothers prespective for the challenge of Monday 22 is 13
See you tomollow
Hi Carmen Ana
You put that we neet to try anothers prespectives for the challenge of Monday 22 is 13
See you tomollow
is 82 the answer of monday because un a cube
noooooooo is 18 yes yes yes
a am the best a now the trick
is 18
pliss carm ANA i now that i have sended many but pliss is 20 a wwas all the aftermoon looking to the mistery square is 20 20 20 20 20 20 20 20 20 20 20 20 20 plis carmen ANA CARMEN ANA
The answer of today and Monday´s challenge is 16.
See you tomorrow =)
is… 4?
is 4
The solucion for the challenge of the 100 meters problen is:
They win the two because in the first round, the girl won by 5 meters of diferences and in the second round she delayed those 5 meters
Paula,
Make sure you read the problem and answer the question, one of them won the race, can you tell me who? Make sure you explain your answer.
Keep trying,
CA
They tied.Because, If she traverses 5 meters faster than he , and she start out 5 meters later, they were coming at the same time because she it will have advanced 5 meters
The runers finish the race at the same time, because the girl run 5 meters faster than the boy, so she advance 5 meters and run at the same speed.
Conclusion: they end tied.
This isn’t a challenge, but I know how to have the resault of the increase and decrease without substracting or adding.
If you have to discount the 9% of something instead of doing it with 9% we subtract 9% from the whole (100%).
So we get 91%. Now we do the same excersise but with the 91%. 91X__:100=___
You are simply GREAT! We´ll talk tomorrow!
I continue:
If we are going to increase the 3% we add it to 100%, that equals 103% and we do the same excersise, but with 103%. 103X___:100=___
hi Carmen Ana:
my answer for this problem is 14 =)
Hello Carmen Ana these are the solucion for chalenge:
Problem 1= is 37 inches.
Problem 2= is$ 53.81
Problem 3= he is 15 years old
the answer for the firts problem is 36
the second 802,6
the second 53.81
the third 15 years
Sorry Guys, try again!
hello the anwer is
BC=80
see you tomorrow
Paula, you got it again!
Carmen Ana :
we ‘ve got the answer for the workers relax challenge.
Monday = Grace
Tuesday= David
Wednesday= Benny
Thursday= Franklin
Friday= Carol
Saturday= Amie
Sunday= Eric
By Paloma and Elena
Monday Carol
Tuesday Amie
Wednesday Eric
Thursaday Franklin
Friday Grace
Saturday David
Sunday Benny
Carmen Ana, I got the solution from the problem of “Workers Relax”:
Monday: Eric
Tuesday: Benny
Wednesday: David
Thursday: Franklin
Friday: Grace
Saturday: Carol
Sunday: Amie
See you tomorrow
Hi, Marta,
Sorry but the answer was already posted!!
Try again,
CA
The answer for unit fraction problem is:
1/8+1/8+1/8+1/8+1/8+1/8+1/8+1/8=8/8=1
Raquel,
Check the problem, all denominators have diferent variables
CA
All the variables have the same value so the answer is 8/8=1
Hi Carmen Ana, the problem says seven different unit fractions but then they were eight, so I did it with 7 and with 8. A possible answer for the “Unit Fraction Problem” is :
With 8 –> a=2; b=4; c=12; d=20; e=24; f=30; g=40; h=60. 120/120=1.
With 7 –> a=2; b=3; c=12; d=30; e=40; f=60; g=120.
Solution for challenge of Tuesday 27
x+x+x+3=369
3x+3=369
3x=369-3
3x=366
x=366/3
x=122
solution
122+123+124=369
Cheking
3*122+3=369
366+3=369
369=369
Paula,
Please read the problem carefully and make sure you check your answer against the problem.
CA
Hi Carmen Ana, I’ve got the answer for the challenge of Tuesday 27:
x+x+2+x+4= 369
3x+6= 369
3x= 369-6
3x= 363
x= 363/3
x= 121
x+2= 123
x+4= 125
121+123+125= 369
And another thing, I check again the “Unit Fraction Problem” and it gaves me the same:
1/2 + 1/3 + 1/12 + 1/30 + 1/40 + 1/60 + 1/120=
60/120 + 40/120 + 10/120 + 4/120 + 3/120 + 2/120 + 1/120= 120/120= 1
121+123+125=369
Im sorry im going to try again I doesn’t read well.
x+1+x+3+x+5=369
3x+9=369
3x=369-9
3x=360
x=360/3
x=120
120+1=121
120+3=123
120+5=125
121+123+125=369
See you tomorrow
Hi Carmen Ana:
I’m giving you the answer for tuesday, 27 of april challenge , x=120
here is the process check
x+(x+4)+(x+5)=369 120+(120+4)+(120+5)=369
2x+4+x+5=369 120+124+125=369
3x+9=369
3x=369-9
3x=360
x=360*3 x=120
x=120
The answer for challenge of wednesday 28:
x+x+8=x+12
2x+8=x+12
2x-x=12-8
x=4
12+4=16 days the lazy gardener take to mow the lawn on his own
Hi Carmen Ana:
I’m giving you the answer for wednesday,28 challenge:
x+x+8=x+12
2x+8=x+12
2x-x=+12-8
2x+x=+4
3x=+4
x=4/3
Energetic: In 12 days complete work. 1 day –> 1/12 of the work. –> 8 days 8/12.
12/12 total work –> 12/12-8/12 = 4/12 is the lazy work on 8 days.
4/12= 1/3 –> 1/3 x 3= 1 (total work.
8 x 3= 24 days.
The lazy takes 24 days to finish the work.